If 0<λ<μ<δ<π2, then secλ+secμ+secδcosecλ+cosecμ+cosecδ lies between
Solution:-
3 secλ < secλ + secμ + sec∂ < 3sec∂
sir please tell me whyy it becomes 3seclambda
3 secλ < secλ + secμ + sec∂ < 3sec∂
sir please tell me whyy it becomes 3seclambda