I wanted to know about the cell reaction at anode and cathode of nickle cadmium cell as fast as possible

Solution:
At Anode: 
Cd(s) + 2OH-(aq)  Cd(OH)2(s) + 2e-
At Cathode:
2NiOOH(s) + 2H2O(l) + 2e-  2Ni(OH)2(s) + 2OH-(aq)

Overall Cell reaction: 
2NiOOH(s) + Cd(s) + 2H2O(l)  Cd(OH)2(s) + 2Ni(OH)2(s)

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