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Solution -
The solution to your 7th query has been provided below.
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7.
i) differential rate equation=
Rate= K[A]1[B]2
ii) when concentration of both A and B is doubled,
Rate= K [2A]1[2B]2
= 8× K[A]1[B]2
The new rate will be 8 times of the actual initial rate .
The solution to your 7th query has been provided below.
For remaining queries, we request you to post them in separate threads to have rapid assistance from our experts.
7.
i) differential rate equation=
Rate= K[A]1[B]2
ii) when concentration of both A and B is doubled,
Rate= K [2A]1[2B]2
= 8× K[A]1[B]2
The new rate will be 8 times of the actual initial rate .