I want the answer of 5&6 question

5.
  Calculate the angle if its supplement is thrice its complement.

6.  An angle is 30 ° more than half of its complement. Find the measure of the angle. 

Q6 Let the angle be x
Complement of x is (90° – x)
Given x = 1/2 × (90° – x) + 30°
⇒ 2x = (90° – x) + 60°
⇒ 3x = 150°
∴ x = 50°

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let the complement be x. so, the supplement will be trice of it.
Therefore
3x+x=180
4x=180
x= 45. complement is 45 and supplement 3*45= 135.
Q6. x/2+x+30= 180
x/2+x=150
2x/2+x/2=150
2x+x=300
x=100 and x-30=70
 
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Q5  let m is the angle s be the supplement and c be the compliment
s=10+3c
180-m=10+3(90-m)
180-m = 10 +270 -3m -100 = -2m m = 50 
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