# HOW WOULD YOU JUSTIFY THE PRESENCE OF 18 ELEMENTS IN THE FIFTH PERIOD OF THE PERIODIC TABLE?

For 5th period, principal quantum number, n  = 5 and values of azimuthal quantum number, l  = 0, 1, 2, 3
Now, filling of orbitals in sub-shells takes place in order of increasing energy of the sub-shell.Since, energy of 4f sub-shell is higher than 5s sub-shell, the sub-shells available for filling are 5s, 4d and 5p
Total number of orbitals = 1 for 5s + 5 for 4d + 3 for 5p
= 1+ 5 + 3
= 9
Therefore, total number of electrons that can be accommodated in 9 orbitals = 9 x 2 = 18
Hence, the number of elements in 5th period is 18.

• 57

When n = 5, l = 0, 1, 2, 3. The order in which the energy of the available orbitals 4d, 5s and 5p increases is 5s < 4d < 5p. The total number of orbitals available are 9. The maximum number of electrons that can be accommodated is 18; and therefore 18 elements are there in the 5th period.

• 20

Electron configuration of Xe:1s2 2s2 2p6 3s2 3p6 4s2 2s2 d10 4p6 5s2 4d10 5p6Looking at the 5th period specifically.5s(2) 4d(10) 5p(6)2+10+6=18

• -17
What are you looking for?