How many PGAL are produced by glycolysis of 3 molecules of glucose ? How many ATP are released by respiration of these PGAL till formation of CO2 & H2O? Please explain the answer which is 6-PGAL-120 ATP.
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Please find below the solution to the asked query
One molecule of glucose breaks down into two molecules of PGAL. Therefore, three molecules of glucose would yield six molecules of PGAL.
The respiratory balance sheet of aerobic respiration of one molecule of glucose can be explained as under:
If one molecule of glucose yields 38 ATPs (under aerobic conditions), then three molecules of it would yield 114 ATPs.
Please find below the solution to the asked query
One molecule of glucose breaks down into two molecules of PGAL. Therefore, three molecules of glucose would yield six molecules of PGAL.
The respiratory balance sheet of aerobic respiration of one molecule of glucose can be explained as under:
| Step | No. of ATP produced |
| Glycolysis | 2NADH2= 2 x 3 = 6ATP 2ATP (Substrate level) Total = 8ATP |
| Linking reaction Pyruvate to Acetyl coenzyme A |
2NADH2= 2 x 3=6 ATP |
| Kreb's cycle | 6NADH 2= 6 x 3=18ATP 2FADH= 2 x 2=4ATP 2ATP (Substrate level) Total= 24ATP |
| Total of all steps | 8+6+24= 38ATP (net gain of ATPs during aerobic respiration of one molecule of glucose) |
If one molecule of glucose yields 38 ATPs (under aerobic conditions), then three molecules of it would yield 114 ATPs.
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