# How many molecules are present in 710 g of chlorine gas (cl 2)? What will be the total number of atoms in it?

The molar mass of chlorine is 35.5 g. So the molar mass of Cl

_{2}gas is 2 X 35.5 = 71 g. Now we know that there are 6.023 X 10

^{23 }particles in one mole of substance. Hence

71 g of Cl

_{2 }= 6.023 X 10

^{23}molecules of Cl

_{2}gas

1 g of Cl

_{2 }= (6.023 X 10

^{23}) / 71 molecules of Cl2 gas

So 710 g of Cl2 = (6.023 X 10

^{23}X 710) / 71 molecules of Cl

_{2}gas

= 6.023 X 10

^{24}molecules of Cl

_{2}gas

A mole of Cl

_{2}gas contains 6.022×10

^{24}molecules, but each molecule of chlorine gas contains two atoms.

Total number of atoms present in Cl

_{2}= (6.023 x 10

^{24 }x 2) = 12.046 x 10

^{24}atoms

Regards,

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