how is the multiplicative inverse of complex number z = a+ib is a /a2+b2 + ib/ a2b 2 Share with your friends Share 1 Rtyrty answered this z= a+ib(a-ib)/a-iba^2+b^2/a-ibso 1/z=a/a^2+b^2 - ib/a^2+b^2 -1 View Full Answer
