How can I write (x3 - (3/8))(x3 + (16/17)) in the standard form?
Answer:
Taking L.C.M of middle term and get As:
Taking L.C.M. and get
Equate equal to Zero and we get
= 0
136 x6 + 77 x3 - 48 = 0 ( Ans )
Taking L.C.M of middle term and get As:
Taking L.C.M. and get
Equate equal to Zero and we get
= 0
136 x6 + 77 x3 - 48 = 0 ( Ans )