hoe to find the hybridization of Fe in K4[Fe(CN)6]......PLEASE EXPLAIN WITH FULL DETAIL

First calculate the oxidation state of iron as follows:

1. Charge on complex ion  = 4-  

 and  oxidation state of CN = -1

 Therefore ,  x + (-6 ) = -4 

oxidation state of Fe  (x) = +2


Electronic configuration of ground state Fe =

Electronic configuration of  Fe(2+) ion =

thus hybridisation will be as follows :

thus the six pair of electrons go to  two 3d  and  4s and 4p orbitals

and thus the hybridisation is

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