Let volume of methane be x L

volume of propane be (5 – x) L

For methane,

CH4 g 2 O2 g CO2 g 2H2O

x 2x

l

Volume reacted:

For propane,

3 8 2 2 2 C H 5O 2CO 4H O

5 x 5 5 x

Volume reacted:

We know, 16 L of oxygen is consumed.

2x + 5 (5 – x) = 16

or, 2x + 25 – 5x = 16

or, 25 – 3x = 16

x = 3

So, volume of methane combusted = 3 L

Moles of methane combusted =

3

22.4

mol

Energy due to methane combusted =

3

890

22.4

kJ

Volume of propane combusted = 2 L

Moles of propane combusted =

2

22.4

mol

Energy due to propane combusted =

2

2220

22.4

kJ

Total energy released

=

3 2

890 2220

22.4 22.4

⎛ ⎞

⎜ ⎟

⎝ ⎠

kJ

= 1

3 890 4440 kJ

22.4

= 1

2670 4440 kJ

22.4

= 317.41 kJ