# Given that HCF (306, 657) = 9, find LCM (306, 657).

Dear Student,

We know :  H.C.F. of two numbers $×$ L.C.M. of two numbers = Product of these numbers

Here , numbers are 306  and 657

And

H.C.F. of ( 306 and 657 ) = 9  , So

9 $×$ L.C.M. of ( 306 and 657 ) =  306 $×$ 657 ,

9 $×$ L.C.M. of ( 306 and 657 ) = 201042 ,

L.C.M. of ( 306 and 657 ) = 22338                                                      ( Ans )

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• 2
LCM Of 306 and 657 is 22338
• 1
As we know, HCF x LCM of two given numbers = Number 1 x Number 2
Therefore, in this case,
HCF x LCM = 9 x LCM
Number 1 x Number 2 = 306 x 657
Equating the equations, we get =
306 x 657 = 9 x LCM
(306 x 657)/9 = LCM
LCM = 22338

Hope this Helps :)
• 1
Given that HCF = 9 and the numbers are 306 and 657 .
LCM = ?
We know that LCM × HCF = product of two numbers
⇒LCM × 9 = 306 × 657
⇒LCM = 201042/9 = 22338 .
• 1
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