From a point on the ground, the angles of elevation of the bottom and the top of a transmission tower fixed at the top of a 20 m high building are 45° and 60° respectively. Find the height of the tower

Dear Student!

Here is the answer to your query.

 


 

Let AB and BC be the transmission tower and Building and D be the point of observation.

Given BC = 20 metres. Let AB = h metres.  Now

∠BDC = 45° and ∠ADC = 60°

In ΔBDC

⇒ DC = 20 m

Now in ΔADC

∴ The height of the tower is 20 metres.

 

Cheers!

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