From a point on the ground, the angles of elevation of the bottom and the top of a transmission tower fixed at the top of a 20 m high building are 45° and 60° respectively. Find the height of the tower
Dear Student!
Here is the answer to your query.
Let AB and BC be the transmission tower and Building and D be the point of observation.
Given BC = 20 metres. Let AB = h metres. Now
∠BDC = 45° and ∠ADC = 60°
In ΔBDC
⇒ DC = 20 m
Now in ΔADC
∴ The height of the tower is 20 metres.
Cheers!