For the reaction, 1 g mole of CaCO3 is enclosed in 5L container CaCO 3(s) - Chemistry - Electrochemistry

Question

For the reaction, 1 g mole of CaCO3?is enclosed in 5L
container?

? ?CaCO?3(s)????CaO(s) + CO?2(g)?

? ? ?K?p?= 1 16 at 1073 K then per cent dissociation of
CaCO?3?is??

? ?(1) Zero? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?
?(2) 6 58%?

? ?(3) 65%? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?
?(4) 100%

Vartika Jain · Accepted Answer

Dear Student,

CaCO3(s)  ↔  CaO(s) + CO2(g)     C                     0                0  C(1-α)             Cα             CαKp = Kc(RT)∆nFor the reaction, ∆n=1So, Kp = KcRTor, Kc=Kp RT          =1
160
0821×1073           =0
0132For the reaction, Kc = [CaO][CO2][CaCO3]Also, since CaCO3 and CaO are solidsSo,[CaCO3]=[CaO]=1or, Kc=[CO2]or, Cα=Kcor, α=KcCHere, C=MassVolume=15So, α=0
0132×51=0 0658or, % α=0 0658×100=6
58%Hence, correct answer is (2)