"For a given?parabola?and a given point (h, k), this cubic in m has three roots say m1, m2, m3?i.e. from (h, k) three?normals?can be drawn to the parabola whose slopes are m1, m2, m3. For this cubic, we have m1?+ m2?+ m3?= 0, m1?m2?+ m2?m3?+ m3?m1?= (2a ? h)/a and m1?m2?m3?= ?k/a." 1. Derive m1?m2?+ m2?m3?+ m3?m1?= (2a ? h)/a.2. Derive m1m2m3=-k/a

Dear Student,

Your question is not clear and appears to be incomplete.Kindly repost the correct question again. You can even post the screenshot of the question.

Regards,

  • 0
What are you looking for?