"For a given?parabola?and a given point (h, k), this cubic in m has three roots say m1, m2, m3?i.e. from (h, k) three?normals?can be drawn to the parabola whose slopes are m1, m2, m3. For this cubic, we have m1?+ m2?+ m3?= 0, m1?m2?+ m2?m3?+ m3?m1?= (2a ? h)/a and m1?m2?m3?= ?k/a." 1. Derive m1?m2?+ m2?m3?+ m3?m1?= (2a ? h)/a.2. Derive m1m2m3=-k/a
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Your question is not clear and appears to be incomplete.Kindly repost the correct question again. You can even post the screenshot of the question.
Regards,