For a chemical reaction, 2A ₂ (g) + 5B ₂ (g) ------- 2A ₂ B5 (g) at temperature - Chemistry - Thermodynamics

Question

For a chemical reaction,
2A ₂ (g) + 5B ₂ (g) -------> 2A ₂ B5 (g)

at temperature = 27°C that is 300Kelvin
The difference between deltaH and deltaE is X
We have to find the ratio X/R
I'm a bit confused to place which value of R here
Please try to answer it before 1:00pm today

Geetha · Accepted Answer

According to thermodynamics∆H - ∆E = RT∆n∆H - ∆ER = T∆nXR = T∆nHere R is a gas constant = 8
314 J K-1 mol-1T = 273 + 27 = 300 K∆n = nP - nR = 2 -7 =  -5so, XR = -5 × 300 = -1500X = -1500 × 8
314 = - 12471 J

For a chemical reaction, 2A ₂ (g) + 5B ₂ (g) -------> 2A ₂ B5 (g) at temperature = 27°C that is... 300Kelvin The difference between deltaH and deltaE is X. We have to find the ratio X/R. I'm a bit confused to place which value of R here. Please try to answer it before 1:00pm today.

For a chemical reaction,
2A ₂ (g) + 5B ₂ (g) -------> 2A ₂ B5 (g)

at temperature = 27°C that is... 300Kelvin
The difference between deltaH and deltaE is X.
We have to find the ratio X/R.
I'm a bit confused to place which value of R here.
Please try to answer it before 1:00pm today.