Dear student, We know that sum of angles around a point is 360° ⇒x3+x3-3+2x+x=360°⇒x3+x3-3+2x+x=360°⇒2x3+3x-3=360°⇒2x3+3x=360°+3⇒2x+9x3=363°⇒11x3=363°⇒x=363°×311⇒x=33°×3⇒x=99°Thus the value of x is 99° Regards

find the value of x:

Dear student,

W e k n o w t h a t s u m o f a n g l e s a r o u n d a p o i n t i s 360 ° . \Rightarrow (\frac{x}{3}) + (\frac{x}{3} - 3) + (2 x) + (x) = 360 ° \Rightarrow \frac{x}{3} + \frac{x}{3} - 3 + 2 x + x = 360 ° \Rightarrow \frac{2 x}{3} + 3 x - 3 = 360 ° \Rightarrow \frac{2 x}{3} + 3 x = 360 ° + 3 \Rightarrow \frac{2 x + 9 x}{3} = 363 ° \Rightarrow \frac{11 x}{3} = 363 ° \Rightarrow x = \frac{363 ° \times 3}{11} \Rightarrow x = 33 ° \times 3 \Rightarrow x = 99 ° T h u s t h e v a l u e o f x i s 99 °

Regards

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