Find the value of tan-1(-tan13π/8)

We havetan-1-tan13π8=tan-1-tan2π-3π8=tan-1--tan3π8                                      As, tan2π-θ=-tanθ=tan-1tan3π8=3π8                                                 As, tan-1tanθ=θ, if  -π2<θ<π2Hence, tan-1-tan13π8=3π8

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-13π/8
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