find the probability of gettin 53 fridays in a leap year
A leap year consists of 366 days, i.e., 52 complete weeks and 2 days remain. These 2 days can be any of the following:
(Mon, Tues), (Tues, Wed), (Wed, Thur), (Thur, Fri), (Fri, Sat), (Sat, Sun)
Thus, total number of cases = 7
Number of cases in which we get a Friday = 2
∴Probability of getting 53 Fridays in a leap year =