find the number whose seventh part exceeds its eighth part by 1
Let the number be 'x'
seventh part of the number = x/7
eighth part of the number = x/8
difference = 1
let us form the equation
x/7 - x/8 = 1
x*8/7*8 - x*7/8*7 = 1
8x/56 - 7x/56 = 1
x/56 = 1
x = 56
hence, the number is 56.
seventh part of the number = x/7
eighth part of the number = x/8
difference = 1
let us form the equation
x/7 - x/8 = 1
x*8/7*8 - x*7/8*7 = 1
8x/56 - 7x/56 = 1
x/56 = 1
x = 56
hence, the number is 56.