find the equation of the circle circumscribing a square ABCD with side l and AB and AD as coordinate axes.
Let the side be "a."
It starts from origin (A).
B=y axis =(0,a).
D=X axis=(a,0).
C= (a,a).
Since AC is diameter and end points are given so.
x(x-a)+y(y-a)=0 [dimetric form]
It starts from origin (A).
B=y axis =(0,a).
D=X axis=(a,0).
C= (a,a).
Since AC is diameter and end points are given so.
x(x-a)+y(y-a)=0 [dimetric form]
