Find the equation of the chord of the circle x²+y²-4x=0 which is bisected at the point (1,1).
{Please mention the requires formula in details)

Here is the answer to your question From the equation of circle, centre is (2,0) and from equation of radius root g^2+f^2-c =0 radius is 2 units. Now the line drawn from centre to chord is perpendicular to chord. Slope ofOD is -1 so slope of AB chord is 1. Now we know a point on chord and slope of chord and can write equation of chord whic is Y-1/x-1=1 y-x =0