Find the difference between heats of reaction at constant pressure and constant volume for the following reaction at 25 C in kJ.

2C6H6 + 15O2 ---------> 12CO2 + 6H2O.

Question

Find the difference between heats of reaction at constant
pressure and constant volume for the following reaction at 25 C in
kJ

2C6H6 + 15O2 ---------> 12CO2 + 6H2O

Geetha · Accepted Answer

The
difference between heats of reaction at constant pressure and
constant volume for the following reaction at 25 C in kJ
2C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(l)∆n = 12 - 15 = -3∆H = ∆E + RT ∆n∆H - ∆E   = RT ∆n                       = (-3) × 8
314 × 10-3 × 298                       =- 7
443 kJ/mole

Find the difference between heats of reaction at constant pressure and constant volume for the following reaction at 25 C in kJ. 2C6H6 + 15O2 ---------> 12CO2 + 6H2O.

Find the difference between heats of reaction at constant pressure and constant volume for the following reaction at 25 C in kJ.

2C6H6 + 15O2 ---------> 12CO2 + 6H2O.