Find the coordinates of the cicumcentre of the triangle whose vertices are (8,6), (8,-2) and (2,-2). Also find its circumradius.
(plz explain step wise)
Hi!
Here is the answer to your question.
Vertices of the triangle are A(8, 6), B(8, –2) and C (2, –2).
Let P(x, y) be the circumcenter of the triangle.
So, PA = PB = PC (Circumcenter is equidistant from the vertices of the triangle)
Cheers!