Find the coordinates of foot of perpendicular from the point (2,3) to the line 3x+4y+8=0.

Let the foot of the perpendicular be B (*x*_{1}, *y*_{1}).

Equation of given line is

Slope of the line, *m* = .

As the point B(*x*_{1}, *y*_{1}) lies on this line, so it satisfies the equation of line.

Now, slope of line AB =

Since AB is normal to the given line.

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