Find The Angle Which Vector A=3i+6j+2k Makes With The Coordinate Axes - Physics - Systems of Particles and Rotational Motion

Question

Find The Angle Which Vector A=3i+6j+2k Makes With The Coordinate
Axes

Srinivasa Ramanujan · Accepted Answer

A = 3i + 6j+ 2k ; B = i (x axis) then,
A B = 3 1 + 6 0 + 2 0 = ABcos theta
3 = 7 cos theta
cos theta = 3/7
theta = cos inverse of 3/7 (where theta is angle with x axis )
simmilarly we can proceeed for y axis ,
vectors in this case are ---- A = 3i + 6j + 2k ; B = j (y axis
)

Regards,
Srinivasa Ramanujan