find tha coordinates of point which are equidistant from these two pionts p(3.0)and q(-3,0).how many points are possible satisfying the conditon?

Answer :

We can find Co - ordinates of a point that is equidistance from  P ( 3 , 0 )  and Q ( - 3 , 0 ) , As  :

First we draw these two points of x  -  plane .

Now , we can see that Every point on y -  axis , is equidistance from given two points P ( 3 , 0 )  and Q ( - 3 , 0 ) .

As  :

We have shown sum points , As  :



O ( 0 , 0 )  , That is 3 unit away from both given points P ( 3 , 0 )  and Q ( - 3 , 0 )  .

C ( 0  , 1 ) , To find distance from both points , we apply distance formula  , As we know 

Distance formula d  =  x2  - x 1 2 +  y2  - y 1 2
So ,
QC  =  0 -  - 3 2 +  1 -0 2 =  0 + 3 2 +  1 2 = 9 +1 = 10 unit 
And
PC =  0 -   3 2 +  1 -0 2 =  - 3 2 +  1 2 = 9 +1 = 10 unit 

So, Point C ( 0 ,1 )  is equidistance from P ( 3 , 0 )  and Q ( - 3 , 0 )  , As we have shown QC =  PC  = 10 unit  .

Now we have point D ( 0 , - 1 ) To find distance from both points , we apply distance formula  , As we know 

Distance formula d  =  x2  - x 1 2 +  y2  - y 1 2
So ,
QD  =  0 -  - 3 2 +  -1 -0 2 =  0 + 3 2 +  -1 2 = 9 +1 = 10 unit 
And
PD =  0 -   3 2 +  -1 -0 2 =  - 3 2 +  -1 2 = 9 +1 = 10 unit 

So, Point D ( 0 ,- 1 )  is equidistance from P ( 3 , 0 )  and Q ( - 3 , 0 )  , As we have shown QD =  PD  = 10 unit  .

Similarly we can show for any point that is lies on y axis is equidistance from P ( 3 , 0 )  and Q ( - 3 , 0 ) .

So, we can say there are infinite number of co - ordinates that are equidistance from P ( 3 , 0 )  and Q ( - 3 , 0 ) .

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the coodinates are 0,0 3,3

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