# Find req.. ..

Here as it is not given that between what points we need to find resistance. So i am considering it between point A and D

From the symmetry current in AO will be same as current in OB

Similarly current CO equal to current in OD

The given circuit can be redrawn as

$R=4+4+\frac{1}{\left(\frac{1}{4}+\frac{1}{8}\right)}=8+\frac{1}{\left(\frac{2+1}{8}\right)}=8+\frac{8}{3}=\frac{32}{3}\phantom{\rule{0ex}{0ex}}\frac{1}{{R}_{AD}}=\frac{1}{4}+\frac{1}{8}+\frac{1}{\frac{32}{3}}=\frac{1}{4}+\frac{1}{8}+\frac{3}{32}=\frac{8+4+3}{32}=\frac{15}{32}\phantom{\rule{0ex}{0ex}}{R}_{AD}=\frac{32}{15}Ohm$

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