Find maximum and minimum values of 3sin^2x - 2cos^2X + 9 Share with your friends Share 1 Aarushi Mishra answered this 3sin2x-2cos2x+9=3sin2x-21-sin2x+9=3sin2x-2+2sin2x+9=5sin2x+7We know0≤sin2x≤10≤5sin2x≤50+7≤5sin2x+7≤5+77≤5sin2x+7≤12Maximum value of given expression=12Minimum value of given expression=7 2 View Full Answer
