find log (2.47*10-29)
please explain with steps and also help me with log .prop
Dear user!
Number in the form of m × 10n where 0 < m < 10 and n is an integer is said to be in the standard form.
The number 2.47 × 10 -29 is in the form m ×10n, where m = 2.47 satisfying the condition 0 < m < 10 and n = -29 is an integer
Thus, the number 2.47 × 10 -29 is in the standard form.
It is also known that if a number m × 10n is in the standard form, then log (m × 10n) = n + log m.
So, log (2.47 × 10 -29) = -29 + log (2.47)
Using a logarithm table, the value of log (2.47) is found as 0.3927.
∴log (2.47 ×10 -29) = -29 + 0.3927 = or -28.6073
Cheers!