find log (2.47*10-29)

please explain with steps and also help me with log .prop

Dear user!

Number in the form of m × 10n where 0 < m < 10 and n is an integer is said to be in the standard form.

The number 2.47 × 10 -29 is in the form m ×10n, where m = 2.47 satisfying the condition 0 < m < 10 and n = -29 is an integer

Thus, the number 2.47 × 10 -29 is in the standard form.

 

It is also known that if a number m × 10n is in the standard form, then log (m × 10n) = n + log m.

So, log (2.47 × 10 -29) = -29 + log (2.47)

 

Using a logarithm table, the value of log (2.47) is found as 0.3927.

  log (2.47 ×10 -29) = -29 + 0.3927 =  or -28.6073

 

Cheers!

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