Find four different solutions of the equation 4 x + 5 y = 20.
The given linear equation in two variables is 4x + 5y = 20.
We can obtain the solution of the equation by substituting the value of one variable and obtaining the value of the other variable.
If we take x = 0, we obtain
4 × 0 + 5y = 20,
5y = 20
or y = 4
Therefore, (0, 4) is a solution of the given equation.
Now, taking y = 0, we obtain
4x + 5 × 0 = 20
4x = 20
x = 5
Therefore, (5, 0) is a solution of the given equation.
Now after this how do you solved the next step. Please expalin in simple words
The given equation i.e., 4x + 5y = 20 can be rewritten as
So, the different solutions can be found out by putting different values of x
Now, for x = 0, y = 4
for x = 5, y = 0
for x = 10, y = -4
for x = -5, y = 8