# Find A vector. B vector if modA vector=2 and modB vector =5 and mod of cross product of vector A and vector B=8

|A| = 2 units.

|B| = 5 units.

|A x B| = 8 units.

Now, |A x B| = |A||B|sinθ

8 = 2*5*sinθ

=>sinθ = 8/10

=> θ = sin^-1 (4/5)

=> θ = 53 deg

Now |A|.|B| = |A||B|cosθ

=> 2*5*cos(53)

=> 10*(3/5) => 6

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