Login

Find a relation between x and y such that the point P(x,y) is equidistant from the points A(7,1) and B(3,5) .

By using distance formula 

and squaring both sides

(x-7)2 +(y-1)2 = (x-3)2+(y-5)2

x2 + 49 -14x + y2 -2y+1= x2 +9 -6x + y2+ 25 -10y

50-14x-2y=34-6x-10y

25 -7x -y=17 -3x -5y

4x-4y=8

x-y=2

  • 92
View Full Answer

 By using distance formula

and squaring both sides

(x-7)2 +(y-1)2 = (x-3)2+(y-5)2

x2 + 49 -14x + y2 -2y+1= x2 +9 -6x + y2+ 25 -10y

50-14x-2y=34-6x-10y

25 -7x -y=17 -3x -5y

4x-4y=8

x-y=2

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

  • 34

PA=PB

SO, PA2=PB2

(X-7)2+(Y-1)2=(X-3)2+(Y-5)2

x2+49-14x+y2+1-2y=x2+9-6x+y2+25-10y

-14x+6x-2y+10y+49-25=0

-8x+8y+24=0

8(-x+y+3)=0

-x+y+3=0

  • 1

Vidushi you forgot +1 and +9 

which would make it 

-8x +8y=16

x-y=2

  • 4

ya...m sorry...i figured it out after looking at the other answers...

  • 6

 no problem :)

  • 1
nagpukar iis right his answer is correct
 
  • 2
i am satisfied Mayank answer .  
  • 6
root
  • -3
If root3 & -root3 are the zeros of polynomial (x)4-(3x)3-(x)2+9x-6 find the other zeroes?
  • 2
By using distance formula and squaring both sides (x-7)2 +(y-1)2 = (x-3)2+(y-5)2 x2 + 49 -14x + y2 -2y+1= x2 +9 -6x + y2+ 25 -10y 50-14x-2y=34-6x-10y 25 -7x -y=17 -3x -5y 4x-4y=8 x-y=2 This is the answer😊
  • -2
use distance formula
  • -2
What are you looking for?