Factorise

ab2+(a-1)b-1

The expression given to us is ab2+(a-1)b-1

Thus,

ab2+(a-1)b-1 = ab2+ab-b-1

= (ab2+ab)-1(b+1), grouping the terms together

= ab(b+1)-1(b+1), taking "ab" common

= (ab-1)(b+1), taking (b+1) common from both terms.

Thus the required factors are (ab-1)(b+1).
 

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