Factorise : a2 + b2 - 2 (ab - ac + bc)

 

  • 52

Hi!

The given expression is a 2 + b 2 – 2(abac + bc ).

a 2 + b 2 – 2(abac + bc ).

= a 2 + b 2 – 2ab + 2ac –2bc

= (ab)2 + 2c (ab)

= (ab)[ (ab) + 2c ]

= (ab) (ab + 2c )

Thus, a 2 + b 2 – 2(ab ac + bc ) = (ab) (ab + 2c )

Cheers!

  • 18
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