f(x)= square root of log2(x2 +1).find the domain and range of functions.

Dear Student,
Please find below the solution to the asked query:

fx=log2x2+1For fx to be defined, argument of log should be strictly positive.x2+1>0which is true for xR, x2 is never negative.Hence domain of fx is -, or xR.Now minimum value of x2+1 is 1 when x=0 and log21=0 and as valueof x2 increases  log2x2+1 will also increase.Hence range of fx is [0,)

Hope this information will clear your doubts about this topic.

If you have any doubts just ask here on the ask and answer forum and our experts will try to help you out as soon as possible.

  • 2
What are you looking for?