explain vertical oscillations of a spring? Share with your friends Share 0 Sanjay Singh answered this Dear student Let a block of mass m is connected to a spring of spring constant k.In the equilibrium position let elongation in the spring x0.for equilibrium of the blockmg=kx0..1Let the block moves a distance x from the equilibrium position .Elongation in the spring is X=x0+xForce of spring on the block by the spring is F1=k(x0+x)Net force on the block isk(x0+x)-mg=makx0+kx-mg=ma (mg=kx0)kx=ma...1a=kxmAs the force is towards the equilibrium position and its magnitude is proportional to the displacement from the mean position so it will perform simple harmonic motionComparing eqn 1 with the standard eqn of SHM we haved2xdt2=ω2xω2=kmω=km2πT=kmT=2πmkRegards 1 View Full Answer
