Explain me the hybridisation of complex [Ni(NH3)6]2+
need the explaination with regard to Valence bond theory as soon as possible!!!
Ni2+: [Ar] 3d8
This configuration creates a problem, because there are eight electrons in the 3d orbitals. Even if we invest the energy necessary to pair the 3d electrons, we can't find two empty 3d orbitals to use to form a set of d2sp3 hybrids.
The valence-bond theory therefore formally distinguishes between "inner-shell" complexes, which use 3d, 4s and 4p orbitals to form a set of d2sp3 hybrids, and "outer-shell" complexes, which use 4s, 4p and 4d orbitals to form sp3d2 hybrid orbitals.