explain how to solve - 1 cost of a dozen banana is rs 36 andd cost of 7 - Maths - Ratio and Proportion

Question

explain how to solve -
1 cost of a dozen banana is rs 36 andd cost of 7 oranges is rs
28 find the ratio of a cost of a banana to an orange
2 divide 102 toffees among sachin and deepa in the ration of 8
:9
3 divide rs 2000 among A , B and C in the ratio of 2 :3:5
4 a sum of money is to be divided between amit and sumit in the
ration of 2:3 how much will each one get if total amount is rs
5000
5 In a school , the ratio of number of boys is 9 :7 find the
number of boys if the total number of students is 3200

Gursheen kaur. · Accepted Answer

1 Cost of a dozen bananas = Rs 36 Cost of 1 banana = $\frac{36}{12} = R s 3$ Cost of 7 oranges = Rs 28 Cost of 1 orange = $\frac{28}{7} = R s 4$ Required ratio = $\frac{\cos t o f b a n a n a}{\cos t o f o r a n g e} = \frac{3}{4}$ 2 Terms of 8: 9 are 8 and 9 Sum of terms = 8+9 = 17 Sachin will get $\frac{8}{17}$ of total toffees and Deepa will get $\frac{9}{17}$ No of toffees will Sachin get = $\frac{8}{17} \times 102 = 48$ and No of toffees will Deepa get = $\frac{9}{17} \times 102 = 54$ 3 Terms of 2: 3:5 are 2,3 and 5 Sum of terms = 2+3+5 = 10 A will get $\frac{2}{10} = \frac{1}{5}$ of total Rs B will get $\frac{3}{10}$ and C will get $\frac{5}{10} = \frac{1}{2}$ No of Rs will A get = $\frac{1}{5} \times 2000 = R s 400$ No of Rs will B get = $\frac{3}{10} \times 2000 = R s 600$ No of Rs will C get = $\frac{1}{2} \times 2000 = R s 1000$ 4 Terms of 2: 3 are 2 and 3 Sum of terms = 2+3 = 5 Amit will get $\frac{2}{5}$ and Sumit will get $\frac{3}{5}$ Sum of money will Amit get = $\frac{2}{5} \times 5000 = R s 2000$ and Sum of money will Sumit get = $\frac{3}{5} \times 5000 = R s 3000$ 5 check the statement of 5th part