Experts please help me with q33
Solution:
2M BaCl2 will show maximum dissociation as Ba2+ and Cl- and Cl-. So it will have more number of solutes binding to the water molecules, and so lesser number of water molecules will be available in 2M BaCl2. 1M NaCl will also show dissociation into Na+ and Cl-ββββββ. Here also, comparative to 1M glucose solution, more number of water molecules will be occupied. Since, glucose does not show dissociation, the number of water molecules freely available will be highest in it. So 1M glucose is expected to have a greater kinetic energy in water molecules.
Please get the concept cross-checked with your chemistry teacher once.
2M BaCl2 will show maximum dissociation as Ba2+ and Cl- and Cl-. So it will have more number of solutes binding to the water molecules, and so lesser number of water molecules will be available in 2M BaCl2. 1M NaCl will also show dissociation into Na+ and Cl-ββββββ. Here also, comparative to 1M glucose solution, more number of water molecules will be occupied. Since, glucose does not show dissociation, the number of water molecules freely available will be highest in it. So 1M glucose is expected to have a greater kinetic energy in water molecules.
Please get the concept cross-checked with your chemistry teacher once.