experts please answer this question and also explain that how is the width of Central Maxima is 2 dlambda/d

Solution : 

Width of central maxima indiffraction=2β=2DλdIf slit width is made doubled then new slit width=2Dλ2d=12×2DλdTherefore width of central maxima will be halvedIntensity, I α EnergyAreaAs slit width is doubled now twice the amount of light falls on the slit and hence energy is double. Also we see that the slit width is halved which means area is halvedI' α 2EnergyArea2I' α 4EnergyAreaI'I=4Hence intensity increases 4 times

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