evaluate sin x - sin a / x-a?
then here's d solutn;
we know that ->sinx-sina=2cos(x+a/2)sin (x-a/2)
so,the questn becomes :
lim x tends to a 2cos(x+a/2) sin(x-a/2)/(x-a)
now multiply 1/2 in both numerator & denominatr. & separate the limits.
then we get, lim x tends to a cos(x+a/2) * lim x tends to a sin(x-a/2)/x-a/2
we know lim x tends to a sin(x-a/2)/x-a/2=1
so, lim x tends to a cos(x+a/2)
put value of a
cos 2a/2
cos a
hope dis helps!!!!!
:)