Equation of normal to curve (1+x^2)=2-x where tangent crosses x-axis is:
x+5y+10=0; 5x+y+10=0; x-5y-10=0; 5x-y-10=0

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Equation of normal to curve (1+x^2)=2-x where tangent crosses
x-axis is:
x+5y+10=0; 5x+y+10=0; x-5y-10=0; 5x-y-10=0

Rahul Raj · Accepted Answer

dear student

please check the question

the independent variable "y" is missing in the equation

post the correct question and we will solve it

regards

Equation of normal to curve (1+x^2)=2-x where tangent crosses x-axis is: x+5y+10=0; 5x+y+10=0; x-5y-10=0; 5x-y-10=0