Did not understand how '+12' became '-12i²'.
please explain...
Solution:-
if you multiply -3√2ix by 2√2ix then you will get -12i2x2 which is equal to +12x2 as i2= -1 where 'i' is an imaginary number which is read as 'iota'. Here, +12 is written as -12i2 which is numerically equal to +12 in order to take 2√2i common for factorisation.
if you multiply -3√2ix by 2√2ix then you will get -12i2x2 which is equal to +12x2 as i2= -1 where 'i' is an imaginary number which is read as 'iota'. Here, +12 is written as -12i2 which is numerically equal to +12 in order to take 2√2i common for factorisation.