Current through a wire increases linearly and it is 8 amp at t = 2 sec and 16 amp at t = 6 sec. Amount of charge passes through wire for t = 0 to t = 5 sec is equal to :-
(1) 60 C
(2) 45 C
(3) 40 C
(4) 75 C
let the current time fucnction of type I(t)= kt +c
putting (8,2) and (16,6) as current and time resp. we get
k=2 and c= 4
integration of I , Idt= kt2/2 + ct = Q (charge)
from0 to 5
45C
option (3)