construct a triangle PQR in which QR=6cm and angle Q = 60degree and PR-PQ=2cm.

We have to construct a triangle with the given data as-

**Step-1**: Draw the base line segment QR= 6 cm.

**Step-2** : From Q, draw an angle of using compass, say ∠XQR.

**Step-3** :Extend the line QX in the opposite direction as well to T. Cut a line segment QS of 2 cm from the line segment QT extended in the opposite side of line segment XQ. Now join the point to R in order to get SR.

**Step-4** : Draw perpendicular bisector AB of line segment SR. Let it intersect QX at point P. Join PQ, PR.

**Thus ΔPQR is the required triangle.**

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