Construct a trapezium ABCD in which AB is parallel to DC having AB=9 cm, CD=5 cm, angle BAD=70 degree , angle DBA=50 degree

Dear Student ,
Please find below the solution to the asked query :

BAD+ADC=180°    Adjacents angles are supplementary in trapezium70°+ADC=180°ADC=110°steps of construction :1 Draw a line segment AB=9 cm .2 Draw a line AP at an angle 70° at point P and  Draw a line BQ at an angle 50° at point Q.3 Line AP and BQ intersects at point D.4 At point draw a line DR at an angle of 110° .5 Taking D as centre , draw an arc of 5 cm , which cuts line DR at point C .6 Join BC .Thus ABCD is the required trapezium .
Hope this information will clear your doubts about the topic .
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible .

  • 11
Plz expert send me the right answer don't send me the similar link as question is different to draw
  • -2
What are you looking for?