construct a rhombus whose diagonals are 6cm , 8cm
It is quite simple!!
I am using a property of rhombus for drawing the figure.
"Diagonals of a rhombus are perpendicular bisectors of each other."
Draw a circle using compass having radius 4cm(8cm bisected)
With same centre draw another circle having radius 3cm(6cm bisected)
Now you have 2 concentric circles.
Now take radius=5cm [sqrt(4*4 + 3*3 )] Pythagorus theorem since the diagonals are perpendicular to each other and the radius being the hypotenuse.
Choose a point on the circle and draw a curve cutting the circle at 2 pts.
Draw the bigger diagonal (Length=8cm using this pt and centre)
Now place the pointer on the other end of the diagonal and draw another curve cutting the circle at 2 pts.
Just join the 2 intersections with the points on the outer circle.
You got it.
