CONSTRUCT A QUADRILATERAL ABCD IN WHICH AB =5.6CM, BC=4 CM,ANGLE A =50 ,ANGLE B=105 , D=80

Answer :
We know from angle sum property of quadrilateral ,

A  +  B + C   + D  =  360° , So

50°  + 105° + C + 80°   =  360°

C =  125°

We follow these steps to construct our quadrilateral ABCD from given information :

Step 1 : Draw line AB  =  5.6 cm 

Step 2 : With the help of protractor we form BAX  =  50°  and ABY  =  105° .

Step 3 : We take radius of 4 cm and center " B " draw an arc that intersect our line BY at " C " .

Step 4 : Now with the help of protractor we form 125° angle at " C " and angle ray intersect line AX at " D " .

We get our required quadrilateral ABCD :


 

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