CONSTRUCT A QUADRILATERAL ABCD IN WHICH AB =5.6CM, BC=4 CM,ANGLE A =50 ,ANGLE B=105 , D=80
Answer :
We know from angle sum property of quadrilateral ,
A + B + C + D = 360 , So
50 + 105 + C + 80 = 360
C = 125
We follow these steps to construct our quadrilateral ABCD from given information :
Step 1 : Draw line AB = 5.6 cm
Step 2 : With the help of protractor we form BAX = 50 and ABY = 105 .
Step 3 : We take radius of 4 cm and center " B " draw an arc that intersect our line BY at " C " .
Step 4 : Now with the help of protractor we form 125 angle at " C " and angle ray intersect line AX at " D " .
We get our required quadrilateral ABCD :
We know from angle sum property of quadrilateral ,
A + B + C + D = 360 , So
50 + 105 + C + 80 = 360
C = 125
We follow these steps to construct our quadrilateral ABCD from given information :
Step 1 : Draw line AB = 5.6 cm
Step 2 : With the help of protractor we form BAX = 50 and ABY = 105 .
Step 3 : We take radius of 4 cm and center " B " draw an arc that intersect our line BY at " C " .
Step 4 : Now with the help of protractor we form 125 angle at " C " and angle ray intersect line AX at " D " .
We get our required quadrilateral ABCD :