Construct a parallogram ABCD in which AB=7cm,AC=10cm,and BD=8cm{remember that the diagonals bisect each other.}
please answer me fast....................
Draw a rough sketch.
We know that diagonals of a parallelogram bisect each other
and
Steps:
1. Draw a ΔOAB with AB = 7 cm, OA = 10 cm and OB = 8 cm
[(a) Draw a line segment AB = 7 cm
(b) With A as centre and radius 5 cm, mark an arc above AB.
(c) with B as centre and radius 4 cm, mark an arc cutting the previous arc at O.
(d) Join OA and OB to get ΔOAB.]
2. Extend AO to a point C such that OC = 5 cm (or AC = 10 cm)
3. Extend BO to a point D such that OD = 4 cm (or BD = 8 cm)
4. Join BC, CD and AD to get required parallelogram ABCD.